The sum of interior angles of a polygon with "n" sides is:
A
180°(n-2)
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B
90°(n-2)
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C
180°(2n-2)
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D
90°(2n-2)
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Question ID: 11132
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The _______ Polygon has all interiors angles and sides equal.
A
Irregular
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B
Convex
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C
Regular
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D
Concave
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Explanation
A Regular Polygon is defined by two specific conditions:
Equiangular: All interior angles are equal.
Equilateral: All sides are of equal length.
Examples:
An Equilateral Triangle (3 sides, all angles 60°).
A Square (4 sides, all angles 90°).
A Regular Pentagon (5 sides, all angles 108°).
In contrast, an Irregular Polygon has sides or angles that are not all equal.
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Circumference of a circle is 88m. Find the radius of the circle.
A
7m
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B
14m
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C
21m
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D
28m
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Explanation
Step 1: Use the formula for the circumference of a circle.
$$\text{Circumference} = 2 \pi r$$
Step 2: Substitute the given value (88 m) into the formula.
$$88 = 2 \times \frac{22}{7} \times r$$
Step 3: Simplify the equation.
$$88 = \frac{44}{7} \times r$$
Step 4: Solve for $r$ .
$$r = \frac{88 \times 7}{44}$$
$$r = 2 \times 7 = 14 \text{ m}$$
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A wire is bent into a square of 484 cm². Find the area of the circle, if the square is reshaped into the circle.
A
44 cm²
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B
616 cm²
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C
308 cm²
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D
1232 cm²
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Explanation
Step 1: Find the side of the square.
$$\text{Area of Square} = \text{side}^2 = 484 \text{ cm}^2$$
$$\text{side} = \sqrt{484} = 22 \text{ cm}$$
Step 2: Find the length of the wire (Perimeter of the square).
Since the wire forms the boundary, its length is the perimeter:
$$\text{Perimeter} = 4 \times \text{side} = 4 \times 22 = 88 \text{ cm}$$
Step 3: Find the radius of the circle.
The same wire (88 cm) is reshaped into a circle. Thus, the Circumference = 88 cm.
$$2 \pi r = 88$$
$$2 \times \frac{22}{7} \times r = 88$$
$$\frac{44}{7} \times r = 88 \implies r = \frac{88 \times 7}{44} = 14 \text{ cm}$$
Step 4: Calculate the area of the circle.
$$\text{Area} = \pi r^2 = \frac{22}{7} \times 14 \times 14$$
$$\text{Area} = 22 \times 2 \times 14 = 616 \text{ cm}^2$$
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Two coins are tossed together. What is the probability of getting one head and one tail?
A
1/4
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B
1/2
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C
3/2
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D
1
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Explanation
Step 1: Identify the Sample Space ($S$ ).
When two coins are tossed, the possible outcomes are:
Head, Head (HH)
Head, Tail (HT)
Tail, Head (TH)
Tail, Tail (TT)
Step 2: Identify the Favorable Outcomes ($E$ ).
The condition is getting exactly one head and one tail :
Step 3: Apply the probability formula.
$$\text{P(1 Head and 1 Tail)} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$$
$$\text{P} = \frac{2}{4} = \frac{1}{2}$$
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A die is rolled once. What is the probability of getting an eyen number greater thạn 2?
A
1/2
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B
1/3
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C
1/6
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D
1/8
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Explanation
Step 1: Identify the total number of possible outcomes.
When a fair die is rolled, the sample space ($S$ ) is:
$$S = \{1, 2, 3, 4, 5, 6\}$$
$$\text{Total outcomes } n(S) = 6$$
Step 2: Identify the favorable outcomes.
The condition is an even number greater than 2 .
Even numbers on a die are: $\{2, 4, 6\}$
Even numbers greater than 2 are: $\{4, 6\}$
$$\text{Favorable outcomes } n(E) = 2$$
Step 3: Apply the probability formula.
$$\text{P(Event)} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$$
$$\text{P(Even > 2)} = \frac{2}{6} = \frac{1}{3}$$
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A bag contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is drawn at random, what is the probability that it is red?
A
3/10
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B
1/2
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C
1/5
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D
2/5
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Explanation
Step 1: Find the total number of possible outcomes.
$$\text{Total balls} = 3 \text{ (Red)} + 2 \text{ (Blue)} + 5 \text{ (Green)} = 10$$
Step 2: Identify the number of favorable outcomes.
$$\text{Number of red balls} = 3$$
Step 3: Apply the probability formula.
$$\text{Probability (P)} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$$
$$\text{P(Red)} = \frac{3}{10}$$
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The graph of linear equation x+2y=2, cuts the y-axis at
A
(1,0)
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B
(2,0)
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C
(0,1)
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D
(0,2)
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Explanation
To find where a graph cuts the y-axis , you must set the value of $x$ to 0 , because every point on the y-axis has an x-coordinate of zero.
Start with the equation:
$$x + 2y = 2$$
Substitute $x = 0$ :
$$0 + 2y = 2$$
Solve for $y$ :
$$2y = 2$$
$$y = 1$$
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Point (3, 4) lies on the graph of the equation 3y = kx + 7. The value of k is
A
4/5
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B
5/3
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C
4/3
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D
4/7
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Explanation
To find $k$ , substitute the coordinates of the point $(x, y) = (3, 4)$ into the given equation:
Substitute the values:
$$3(4) = k(3) + 7$$
Simplify the terms:
$$12 = 3k + 7$$
Isolate the term with $k$ :
$$12 - 7 = 3k$$
$$5 = 3k$$
Solve for $k$ :
$$k = \frac{5}{3}$$
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The linear equation 3x-11y=10 has
A
Unique solution
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B
Two solutions
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C
Infinitely many solutions
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D
No solutions
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Explanation
The linear equation $3x - 11y = 10$ has infinitely many solutions .
In coordinate geometry, a linear equation with two variables (like $x$ and $y$ ) represents a straight line on a graph.
Continuous Line: Every point located on that line is a solution to the equation.
Infinite Points: Since a line extends infinitely in both directions, there are an infinite number of $(x, y)$ coordinate pairs that satisfy the equation.
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The distance covered by a tire of 84 cm radius in 4 revolutions is
A
1056 cm
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B
2112 cm
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C
840 cm
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D
1840 cm
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Explanation
1. Find the Circumference ($C$ ):
Using the formula $C = 2\pi r$ , where $r = 84 \text{ cm}$ and $\pi \approx \frac{22}{7}$ :
$$C = 2 \times \frac{22}{7} \times 84$$
$$C = 2 \times 22 \times 12$$
$$C = 528 \text{ cm}$$
2. Multiply by Revolutions ($n$ ):
Total Distance = $C \times n$ , where $n = 4$ :
$$\text{Distance} = 528 \times 4$$
$$\text{Distance} = 2112 \text{ cm}$$
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A circular pond has a circumference of 22 km. What is its diameter?
A
15 Km
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B
1.5 Km
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C
0.7 Km
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D
7 Km
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Explanation
The circumference ($C$ ) of a circle is related to its diameter ($d$ ) by the formula:
$$C = \pi \times d$$
Given the circumference is 22 km and using the common approximation for $\pi \approx \frac{22}{7}$ :
Substitute the values: $22 = \frac{22}{7} \times d$
Solve for $d$ : $d = 22 \div \frac{22}{7}$
Multiply by the reciprocal: $d = 22 \times \frac{7}{22}$
Simplify: $d = 7$
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The area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm is
A
82 cm²
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B
410 cm²
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C
41 cm²
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D
820 cm²
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Explanation
The area of a rhombus ($A$ ) is calculated using the product of its diagonals ($d_1$ and $d_2$ ) divided by two:
$$A = \frac{1}{2} \times d_1 \times d_2$$
Multiply the diagonals: $10 \times 8.2 = 82$
Divide by 2: $82 \div 2 = 41$
Result: $41 \text{ cm}^2$
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Volume of a cuboid of length (1), width (b) and height (h) is
A
lbh
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B
1b+bh+ hl
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C
2 (1+b) h
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D
2 (lb +bh + hl)
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Explanation
The volume of a cuboid is calculated by multiplying its three dimensions: length ($l$ ), width ($b$ ), and height ($h$ ).
$$V = l \times b \times h$$
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Producers' total revenue will decrease if
A
the price rises and demand is elastic
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B
income increases and the good is a normal good
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C
the price falls and demand is elastic
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D
income falls and the good is an inferior good.
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Explanation
the price rises and demand is elastic
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The solution of y` + y=x+ 1 + e* will be
A
y = Ce⁻⁵ˣ+4 x
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B
y = 2Ce⁻⁴ˣ + x - 1
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C
y = Ce⁻²ˣ + 2x + 5
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D
y = Ce* + x
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Explanation
y = C e^ + x *
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Which ofthe following differential equations is NOT exact?
A
(y²-x)dx+(2xy)dy=0
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B
(x²+y²)dx+(2xy)dy= 0
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C
(2xy+y²)dx+(x²+2xy)dy=0
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D
(3x²-y)dx+(3y²-x²)dy=0
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Explanation
(3x² - y)dx + (3y² - x²)dy = 0
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The equation dy/dx + y = y² sinx is an example of:
A
Homogeneous equation
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B
Exact equation
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C
Bernoulli equation
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D
Linear equation
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Explanation
Bernoulli equation
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∫cot²xcosec⁴x dx is equal to
A
cot³x/3 + cosec⁵x/5
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B
- cot³x/3 - cosec⁵x/5
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C
cosec³x/3 - cot⁵x/5
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D
- cosec³x/3 + cot⁵x/5
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Explanation
–cot³x/3 – cosec⁵x/5
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F(x) = Sin¹x dx over the limits 0 to 1 is
A
Zero
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B
2
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C
27-1
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D
π/2-1
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Let f(x) = |sinx|, the set of points where f(x) is not differentiable over (-∞, ∞) is:
A
Empty
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B
{nne Z}
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C
{(2n+1/2) π|ηεZ}
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D
{x ∈ R |sinx =1}
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The derivative of y = cot(x) - cosec(x) is:
A
- cosec²(x) + cosec(x)cot(x)
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B
- cot²(x) + cosec²(x)
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C
- cosec(x)cot(x) - cosec²(x)
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D
cosec²(x) + cosec(x)cot(x)
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Explanation
–cosec²(x) + cosec(x)cot(x)
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Given f(x) =In f(x), which ofthe following statements about its concavity is correct?
A
The graph off(x) is concave upward for all x> 0
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B
The graph off(x) has a point of inflection at x =1
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C
The graph of f(x) is concave downward for all x>0
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D
The function has no interval of concavity
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Explanation
The graph of f(x) is concave downward for all x > 0
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The equation of the circle is x² + y2 - 6x + 8y+9=0. The equation ofthe tangent to the circle at the point (7, -4) is
A
x=7
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B
y=-4
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C
x+y = 3
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D
x-y = 2
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= 5 && reportMessage.length <= 2000) { $wire.submitReport(9903, reportMessage); reportOpen = false; reportMessage = ''; }"
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The Quadrilateral PQRS has vertices at P = (1, 2), Q = (4 , -1), R = (7, 2), and S=(4, 5). It will be a
A
Parallelogram
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B
Rectangle
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C
Rhombus
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D
Square
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Question ID: 9902
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= 5 && reportMessage.length <= 2000) { $wire.submitReport(9902, reportMessage); reportOpen = false; reportMessage = ''; }"
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A company produced a product using 5 units of labour and 3 units of capital, and the total cost was₹91. By using 6 units of labour and 2 units ofcapital, the cost was ₹ 88. Using the determinant method, the cost per unit of labour and capital (in - approximately) will be
A
5,7
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B
10, 13
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C
9, 15
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D
13, 17
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Question ID: 9901
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The points A (1, 2), В (3, 5), C (k, 6) form a triangle of area 5 square units. The possible values of k is.
A
k=2 or k=7
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B
k= 2/5 or k =-½
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C
k= 1/3 or k =7
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D
k=2/5 or k =7
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Explanation
k = 1/3 or k = 7
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Out of 500 residents in a township, 320 subscribe to Newspaper A, 180 subscribe to Newspaper B, 150 subscribe to both A and B. Find how many residents subscribe only to Newspaper B.
A
30
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B
130
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C
150
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D
180
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Question ID: 9899
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Suppose A, B, and C are subsets of a universal set X. Which one of the following set identities is NOT universally valid?
A
n(AUB) = n(A-B)-n(A)+n(AnB)
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B
n(A-B) = n(A)-n(AnB)
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C
An(BUC)=(ANB)U(ANc)
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D
AX(BnC)=(AXB)n(AXC)
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Explanation
n(A ∪ B) = n(A − B) − n(A) + n(A ∩ B) is NOT universally valid.
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Question ID: 9898
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Two goods trains, each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
A
12 sec
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B
24 sec
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C
48 sec
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D
60 sec
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Explanation
Relative speed = 75 km/hr = 75?(5/18)=20.83 m/s. Distance=500m. Time=500/20.83?24 sec.
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